-1000x^2+40000x+1200000=0

Solution for -1000x^2+40000x+1200000=0 equation:

-1000x^2+40000x+1200000=0

a = -1000; b = 40000; c = +1200000;
Δ = b2-4ac
Δ = 400002-4·(-1000)·1200000
Δ = 6400000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400000000}=80000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40000)-80000}{2*-1000}=\frac{-120000}{-2000}
=+60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40000)+80000}{2*-1000}=\frac{40000}{-2000}
=-20
$